Wednesday, July 13, 2011

Calculus Problem Finding Areas of Curves?

Points of intersections (2;1) & (-18;-9) , area = integral from -9 to 1 of -(y^2)/4 +9/4 -2y , area=125/3=41.67
Posted by Unknown at 11:43 PM

No comments:

Post a Comment

Subscribe to: Post Comments (Atom)